| 1 | 1 | def solve(puzzle: str) -> dict[str, int] | None: |
| 2 | | pass |
| 2 | """ |
| 3 | Solve an alphametics puzzle. |
| 4 | |
| 5 | Args: |
| 6 | puzzle: A string representing the puzzle (e.g., "SEND + MORE == MONEY") |
| 7 | |
| 8 | Returns: |
| 9 | A dictionary mapping letters to digits, or None if no solution exists |
| 10 | """ |
| 11 | # Edge Case: Empty or None puzzle |
| 12 | if not puzzle: |
| 13 | return None |
| 14 | |
| 15 | # Parse the puzzle |
| 16 | parts = puzzle.replace("==", "=").replace(" ", "").split("=") |
| 17 | |
| 18 | # Edge Case: Invalid puzzle format |
| 19 | if len(parts) != 2: |
| 20 | return None |
| 21 | |
| 22 | right_side = parts[1] |
| 23 | left_expression = parts[0] |
| 24 | |
| 25 | # Extract operator and operands |
| 26 | operators = [] |
| 27 | operands = [] |
| 28 | current_operand = "" |
| 29 | |
| 30 | for char in left_expression: |
| 31 | if char in "+-*": |
| 32 | operators.append(char) |
| 33 | operands.append(current_operand) |
| 34 | current_operand = "" |
| 35 | else: |
| 36 | current_operand += char |
| 37 | operands.append(current_operand) |
| 38 | |
| 39 | # Edge Case: No operands |
| 40 | if not operands or any(not op for op in operands): |
| 41 | return None |
| 42 | |
| 43 | left_sides = operands |
| 44 | |
| 45 | # Edge Case: No terms on the left side |
| 46 | if not left_sides: |
| 47 | return None |
| 48 | |
| 49 | # Get all unique letters |
| 50 | letters = set() |
| 51 | for part in left_sides + [right_side]: |
| 52 | letters.update(part) |
| 53 | |
| 54 | # Edge Case: No letters in puzzle |
| 55 | if not letters: |
| 56 | return None |
| 57 | |
| 58 | # Get first letters (can't be zero) |
| 59 | first_letters = {word[0] for word in left_sides + [right_side]} |
| 60 | |
| 61 | # Edge Case: More than 10 unique letters (impossible to solve) |
| 62 | if len(letters) > 10: |
| 63 | return None |
| 64 | |
| 65 | letters = list(letters) |
| 66 | |
| 67 | # Try all possible digit assignments |
| 68 | from itertools import permutations |
| 69 | |
| 70 | for perm in permutations(range(10), len(letters)): |
| 71 | mapping = dict(zip(letters, perm)) |
| 72 | |
| 73 | # Edge Case: Leading zero |
| 74 | if any(mapping[letter] == 0 for letter in first_letters): |
| 75 | continue |
| 76 | |
| 77 | # Calculate left side value with proper operator handling |
| 78 | numbers = [] |
| 79 | for word in left_sides: |
| 80 | number = 0 |
| 81 | for letter in word: |
| 82 | number = number * 10 + mapping[letter] |
| 83 | numbers.append(number) |
| 84 | |
| 85 | # Apply operators in sequence |
| 86 | if not operators: |
| 87 | left_value = numbers[0] if numbers else 0 |
| 88 | else: |
| 89 | left_value = numbers[0] |
| 90 | for i, op in enumerate(operators): |
| 91 | if op == "+": |
| 92 | left_value += numbers[i + 1] |
| 93 | elif op == "-": |
| 94 | left_value -= numbers[i + 1] |
| 95 | elif op == "*": |
| 96 | left_value *= numbers[i + 1] |
| 97 | |
| 98 | # Calculate right side value |
| 99 | right_value = 0 |
| 100 | for letter in right_side: |
| 101 | right_value = right_value * 10 + mapping[letter] |
| 102 | |
| 103 | # Check if equation is satisfied |
| 104 | if left_value == right_value: |
| 105 | return mapping |
| 106 | |
| 107 | # Edge Case: No solution found |
| 108 | return None |
| 109 | # Handled Edge Cases: Empty or None puzzle, Invalid puzzle format, No terms on the left side, No letters in puzzle, More than 10 unique letters (impossible to solve), Leading zero, No solution found |