| 1 | 1 | def solve(puzzle: str) -> dict[str, int] | None: |
| 2 | | pass |
| 2 | """ |
| 3 | Solve an alphametics puzzle. |
| 4 | |
| 5 | Args: |
| 6 | puzzle: A string representing the alphametics puzzle (e.g., "SEND + MORE == MONEY") |
| 7 | |
| 8 | Returns: |
| 9 | A dictionary mapping letters to digits that solves the puzzle, or None if no solution exists. |
| 10 | |
| 11 | The function handles the following edge cases: |
| 12 | - Invalid puzzle format |
| 13 | - Leading zeros in numbers |
| 14 | - Duplicate letter assignments |
| 15 | - No solution found |
| 16 | """ |
| 17 | # Edge Case: Empty or None puzzle |
| 18 | if not puzzle: |
| 19 | return None |
| 20 | |
| 21 | # Parse the puzzle |
| 22 | # Edge Case: Invalid puzzle format (no '=' or incorrect structure) |
| 23 | if '=' not in puzzle: |
| 24 | return None |
| 25 | |
| 26 | try: |
| 27 | # Handle both "=" and "==" operators |
| 28 | if ' == ' in puzzle: |
| 29 | left_side, right_side = puzzle.split(' == ') |
| 30 | elif ' = ' in puzzle: |
| 31 | left_side, right_side = puzzle.split(' = ') |
| 32 | else: |
| 33 | # Handle cases without spaces around = |
| 34 | parts = puzzle.split('=') |
| 35 | if len(parts) != 2: |
| 36 | return None |
| 37 | left_side, right_side = parts[0], parts[1] |
| 38 | |
| 39 | addends = [word.strip() for word in left_side.split('+')] |
| 40 | result = right_side.strip() |
| 41 | except ValueError: |
| 42 | return None |
| 43 | |
| 44 | # Edge Case: Empty words in puzzle |
| 45 | if not all(addends) or not result: |
| 46 | return None |
| 47 | |
| 48 | # Get all unique letters |
| 49 | letters = set() |
| 50 | for word in addends + [result]: |
| 51 | letters.update(word) |
| 52 | |
| 53 | # Edge Case: More than 10 unique letters (impossible to assign unique digits) |
| 54 | if len(letters) > 10: |
| 55 | return None |
| 56 | |
| 57 | # Get first letters (can't be zero) |
| 58 | first_letters = {word[0] for word in addends + [result]} |
| 59 | |
| 60 | # Convert to sorted list for consistent ordering |
| 61 | letters = list(letters) |
| 62 | |
| 63 | # Try all possible digit assignments |
| 64 | from itertools import permutations |
| 65 | |
| 66 | # Edge Case: Handle puzzles with no letters |
| 67 | if not letters: |
| 68 | return {} |
| 69 | |
| 70 | # Try all permutations of digits for the letters |
| 71 | for perm in permutations(range(10), len(letters)): |
| 72 | mapping = dict(zip(letters, perm)) |
| 73 | |
| 74 | # Check if any first letter is assigned zero |
| 75 | # Edge Case: Leading zero in any number |
| 76 | if any(mapping[letter] == 0 for letter in first_letters): |
| 77 | continue |
| 78 | |
| 79 | # Calculate the sum of addends |
| 80 | addend_values = [] |
| 81 | for word in addends: |
| 82 | value = 0 |
| 83 | for letter in word: |
| 84 | value = value * 10 + mapping[letter] |
| 85 | addend_values.append(value) |
| 86 | |
| 87 | # Calculate the result value |
| 88 | result_value = 0 |
| 89 | for letter in result: |
| 90 | result_value = result_value * 10 + mapping[letter] |
| 91 | |
| 92 | # Check if the equation is satisfied |
| 93 | if sum(addend_values) == result_value: |
| 94 | return mapping |
| 95 | |
| 96 | # Edge Case: No valid solution found |
| 97 | return None |
| 98 | |
| 99 | # Handled Edge Cases: Empty or None puzzle, Invalid puzzle format, Empty words in puzzle, More than 10 unique letters, Leading zero in any number, No valid solution found |