| 1 | 1 | def encode(plain_text: str, a: int, b: int) -> str: |
| 2 | pass | |
| 2 | m = 26 # Size of the alphabet | |
| 3 | ||
| 4 | # Edge Case: Check if a and m are coprime | |
| 5 | if gcd(a, m) != 1: | |
| 6 | raise ValueError("a and m must be coprime.") | |
| 7 | ||
| 8 | result = [] | |
| 9 | plain_text = plain_text.lower() | |
| 10 | ||
| 11 | for char in plain_text: | |
| 12 | if char.isalpha(): | |
| 13 | # Convert letter to number (0-25) | |
| 14 | i = ord(char) - ord('a') | |
| 15 | # Apply encryption formula | |
| 16 | encrypted_i = (a * i + b) % m | |
| 17 | # Convert back to letter | |
| 18 | encrypted_char = chr(encrypted_i + ord('a')) | |
| 19 | result.append(encrypted_char) | |
| 20 | elif char.isdigit(): | |
| 21 | # Edge Case: Keep digits as they are | |
| 22 | result.append(char) | |
| 23 | # Edge Case: Ignore spaces and punctuation (they are excluded) | |
| 24 | ||
| 25 | # Group into chunks of 5 characters | |
| 26 | grouped_result = [] | |
| 27 | for i in range(0, len(result), 5): | |
| 28 | grouped_result.append(''.join(result[i:i+5])) | |
| 29 | ||
| 30 | return ' '.join(grouped_result) | |
| 3 | 31 | |
| 4 | 32 | |
| 5 | 33 | def decode(ciphered_text: str, a: int, b: int) -> str: |
| 6 | pass | |
| 34 | m = 26 # Size of the alphabet | |
| 35 | ||
| 36 | # Edge Case: Check if a and m are coprime | |
| 37 | if gcd(a, m) != 1: | |
| 38 | raise ValueError("a and m must be coprime.") | |
| 39 | ||
| 40 | # Find the modular multiplicative inverse of a | |
| 41 | a_inv = None | |
| 42 | for x in range(1, m): | |
| 43 | if (a * x) % m == 1: | |
| 44 | a_inv = x | |
| 45 | break | |
| 46 | ||
| 47 | # Edge Case: This should not happen if gcd check passed, but just in case | |
| 48 | if a_inv is None: | |
| 49 | raise ValueError("a and m must be coprime.") | |
| 50 | ||
| 51 | result = [] | |
| 52 | ciphered_text = ciphered_text.replace(' ', '') # Remove spaces | |
| 53 | ||
| 54 | for char in ciphered_text: | |
| 55 | if char.isalpha(): | |
| 56 | # Convert letter to number (0-25) | |
| 57 | y = ord(char) - ord('a') | |
| 58 | # Apply decryption formula | |
| 59 | decrypted_i = (a_inv * (y - b)) % m | |
| 60 | # Convert back to letter | |
| 61 | decrypted_char = chr(decrypted_i + ord('a')) | |
| 62 | result.append(decrypted_char) | |
| 63 | elif char.isdigit(): | |
| 64 | # Edge Case: Keep digits as they are | |
| 65 | result.append(char) | |
| 66 | # Edge Case: Ignore any other characters (though input should only have letters, digits, and spaces) | |
| 67 | ||
| 68 | return ''.join(result) | |
| 69 | ||
| 70 | ||
| 71 | def gcd(x: int, y: int) -> int: | |
| 72 | # Helper function to compute greatest common divisor | |
| 73 | while y: | |
| 74 | x, y = y, x % y | |
| 75 | return x | |
| 76 | ||
| 77 | # Handled Edge Cases: | |
| 78 | # 1. Check if 'a' and 'm' are coprime in both encode and decode functions | |
| 79 | # 2. Keep digits unchanged during encryption and decryption | |
| 80 | # 3. Ignore spaces and punctuation during encryption | |
| 81 | # 4. Group ciphertext into chunks of 5 characters separated by spaces | |
| 82 | # 5. Remove spaces from ciphertext during decryption | |
| 83 | # 6. Handle case where modular multiplicative inverse might not be found (defensive programming) |
| Test Name | Status |
|---|---|
test_decode_a_sentence | Pass |
test_decode_all_the_letters | Pass |
test_decode_exercism | Pass |
test_decode_numbers | Pass |
test_decode_with_a_not_coprime_to_m | Pass |
test_decode_with_no_spaces_in_input | Pass |
test_decode_with_too_many_spaces | Pass |
test_encode_all_the_letters | Pass |
test_encode_deep_thought | Pass |
test_encode_mindblowingly | Pass |
test_encode_no | Pass |
test_encode_numbers | Pass |
test_encode_o_m_g | Pass |
test_encode_omg | Pass |
test_encode_with_a_not_coprime_to_m | Pass |
test_encode_yes | Pass |
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